AI Math Solver
Resources
Questions
Pricing
Login
Register
Home
>
Questions
>
Find Ones Place Digit in 6×6 Grid Minus Locked Squares
Mathematics
Grade 3 (Primary School)
Question Content
Given a 6×6 grid (square) with 4 locked squares (yellow with locks), determine the digit in the ones place of the result of \( 6 \times 6 - \text{[number of locked squares]} \). The expression is \( \square \times \square - \square \), and the first \( \square \) is for the ones place.
Correct Answer
2
Detailed Solution Steps
1
Step 1: Calculate the total number of squares in the 6×6 grid. Using the area formula for a square (side × side), we get \( 6 \times 6 = 36 \).
2
Step 2: Count the number of locked squares. From the image, there are 4 locked squares (yellow with locks).
3
Step 3: Subtract the number of locked squares from the total: \( 36 - 4 = 32 \).
4
Step 4: Identify the digit in the ones place of 32. The ones place (units digit) of 32 is 2.
Knowledge Points Involved
1
Multiplication of Integers
Multiplying two integers (e.g., \( 6 \times 6 \)) to find the total number of items in a rectangular or square arrangement (area of a square here).
2
Subtraction of Integers
Subtracting a smaller integer from a larger one (e.g., \( 36 - 4 \)) to find the remaining quantity after removing a subset.
3
Place Value (Ones Place)
The rightmost digit in a number represents the ones place (units place), indicating how many single units are in the number (e.g., the ones place of 32 is 2).
4
Counting Objects
Identifying and counting specific objects (locked squares) within a larger set to determine a subtraction amount.
Loading solution...
