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Primary School Grade 3 Basic Single-digit Divisor Division Practice Problems
Mathematics
Grade 3 of Primary School
Question Content
Calculate the following division problems: 5 ÷ 5 = □; 6 ÷ 3 = □; 18 ÷ 2 = □; 28 ÷ 4 = □
Correct Answer
1; 2; 9; 7
Detailed Solution Steps
1
Step 1: Solve 5 ÷ 5. Using the basic division rule that any non-zero number divided by itself equals 1, so 5 ÷ 5 = 1.
2
Step 2: Solve 6 ÷ 3. Recall the multiplication fact 3×2=6, so the quotient of 6 divided by 3 is 2.
3
Step 3: Solve 18 ÷ 2. Use the multiplication fact 2×9=18, so 18 divided by 2 equals 9.
4
Step 4: Solve 28 ÷ 4. Use the multiplication fact 4×7=28, so 28 divided by 4 equals 7.
Knowledge Points Involved
1
Basic Division of Non-zero Number by Itself
This rule states that any non-zero integer divided by itself results in 1. It is a fundamental division property, used for quick calculation when the dividend and divisor are the same positive integer.
2
Relationship Between Multiplication and Division
Division is the inverse operation of multiplication. For any three numbers a, b, c where b≠0, if a×b=c, then c÷b=a and c÷a=b. This relationship is used to solve division problems by recalling corresponding multiplication facts, which is a core method for learning basic division in primary school.
3
Single-digit Divisor Division
This refers to division operations where the divisor is a single positive integer (1-9). It is the foundational form of division learning, requiring mastery of multiplication tables to quickly find the quotient, and it lays the groundwork for more complex division operations later.
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